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5#
发表于 2011-7-13 16:27
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I got P(success)=0.2866 (0.70x.85x.80x.75... something like that)
Remember, p(Success) is the product of SUCCESS probabilities, the question gives us failure probabilities.
I multiply P(success) by CF final (10 million), I get 2,866,000. Then I enter this as my CF5, enter -1million as Cf0, and calculate NPV at the given rate (18% I think)
I use the CF function, not the PV, FV function. |
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