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In a positively skewed distribution, the:
A)
median equals the mean.
B)
mean is greater than the median.
C)
mean is less than the median.



In a right-skewed distribution, there are large positive outliers. These outliers increase the mean of the distribution but have little effect on the median. Therefore, the mean is greater than the median.

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If a distribution is positively skewed, then generally:
A)
mean < median < mode.
B)
mean > median < mode.
C)
mean > median > mode.



When a distribution is positively skewed the right side tail is longer than normal due to outliers. The mean will exceed the median, and the median will generally exceed the mode because large outliers falling to the far right side of the distribution can dramatically influence the mean.

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Twenty Level I CFA candidates in a study group took a practice exam and want to determine the distribution of their scores. When they grade their exams they discover that one of them skipped an ethics question and subsequently filled in the rest of his answers in the wrong places, leaving him with a much lower score than the rest of the group. If they include this candidate’s score, their distribution will most likely:
A)
have a mode that is less than its median.
B)
have a mean that is less than its median.
C)
be positively skewed.



With the low outlier included, the distribution will be negatively skewed. For a negatively skewed distribution, the mean is less than the median, which is less than the mode.

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In a negatively skewed distribution, what is the order (from lowest value to highest) for the distribution’s mode, mean, and median values?
A)
Median, mode, mean.
B)
Mode, mean, median.
C)
Mean, median, mode.



In a negatively skewed distribution, the mean is less than the median, which is less than the mode.

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In a positively skewed distribution, what is the order (from lowest value to highest) for the distribution’s mode, mean, and median values?
A)
Mean, median, mode.
B)
Mode, mean, median.
C)
Mode, median, mean.



In a positively skewed distribution, the mode is less than the median, which is less than the mean.

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thanks for sharing!

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