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Reading 11- LOS F (Part 2): : Q7-8

7What is the t-statistic for the slope of the regression line?

A)   7.7025.

B)   3.1820.

C)   2.9600.

D)   59.4500.

8variable y is regressed against a single variable x across 24 observations. The value of the slope is 1.14, and the constant is 1.3. The mean value of x is 1.10, and the mean value of y is 2.67. The standard deviation of the x variable is 1.10, and the standard deviation of the y variable is 2.46. The sum of squared errors is 89.7. For an x value of 1.0, what is the 95 percent confidence interval for the y value?

A)   -1.68 to 6.56.

B)   0.59 to 4.30.

C)   0.79 to 4.09.

D)   -1.83 to 6.72.

[此贴子已经被作者于2008-4-1 17:54:16编辑过]

7What is the t-statistic for the slope of the regression line?

A)   7.7025.

B)   3.1820.

C)   2.9600.

D)   59.4500.

The correct answer was A)

Tb = (b1hat – b1) / sb1 = ( 0.2796 – 0 ) / 0.0363 = 7.7025.

8variable y is regressed against a single variable x across 24 observations. The value of the slope is 1.14, and the constant is 1.3. The mean value of x is 1.10, and the mean value of y is 2.67. The standard deviation of the x variable is 1.10, and the standard deviation of the y variable is 2.46. The sum of squared errors is 89.7. For an x value of 1.0, what is the 95 percent confidence interval for the y value?

A)   -1.68 to 6.56.

B)   0.59 to 4.30.

C)   0.79 to 4.09.

D)   -1.83 to 6.72.

The correct answer was D)

First the standard error of the estimate must be calculated—it is equal to the square root of the mean squared error, which is equal to the sum of squared errors divided by the number of observations minus 2 = (89.7 / 22)1/2 = 2.02. The standard deviation of the prediction is equal to the squared standard error of the estimate multiplied by {1 + 1/n + (x u)2/[(n 1)sx2]}1/2 = {2.022 × [1 + 1/24 + (1.0 1.1)2/(23 × 1.12)]}1/2 = 2.06. The prediction value is 1.3 + (1.0 × 1.14) = 2.44. The t-value for 22 degrees of freedom is 2.074. The endpoints of the interval are 2.44 ± 2.074 × 2.06 = 1.83 and 6.72.

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