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标题: Quant Questions [打印本页]

作者: rosewhite    时间: 2011-7-11 18:38     标题: Quant Questions

An analyst determines that approximately 99 percent of the observations of daily sales for a company are within the intervals from $230,000 to $480,000 and that daily sales for the company are normally distributed. The standard deviation of daily sales for the company is closest to:

A. 41,667
B. 62,500
C. 83,333
作者: dece2011    时间: 2011-7-11 18:38

That is the correct answer, but I am interested in seeing how people arrived to that answer.
作者: mnieman    时间: 2011-7-11 18:38

i get 48,449

125,000 / 2.58

...
作者: thisisbrianly    时间: 2011-7-11 18:38

Shouldn't the 99% Confidence Interval be 2.58 instead of using Chebyshev's inequality...which gives 3?
作者: suyash1989    时间: 2011-7-11 18:38

48,449 is technically correct. However, the 41,667 is obtained using the approximate rule that 99% of observations will fall within +/- 3 standard deviations of the mean.

Mean = 355000
3 std. dev. = (480000 - 355000) = 125000
1 std. dev = 41,666.67
作者: eagles_dare13    时间: 2011-7-11 18:38

got ya - using 3 instead of 2.58
作者: Siddimaula    时间: 2011-7-11 18:38

I don't get it.

125,000/2.576 = Standard Error
$48,524.84 = SE
Standard Deviation/Sqrt(n) = $48,524.84
Given 62,500 and 83,333 as standard deviations...
A makes no sense.
B. (62500/48524)^2=n n=1.659
C. (83333/48524)^2=n n=2.9493

Probably C neh?
作者: ajpheif16    时间: 2011-7-11 18:38

technically for z score 99.7% = 3 but in this case its using 3 for 99% instead of 2.58

So 230+480 / 2 = 355 = mean

355 +- 3(X) = 480
480 - 355 = 125
125/3 = 41667



Edited 1 time(s). Last edit at Tuesday, June 2, 2009 at 12:33PM by chung.da.neu.
作者: ramdabom    时间: 2011-7-11 18:38

sujian Wrote:
-------------------------------------------------------
> Nope, still don't get it, why does 125k/3 =
> standard deviation instead of standard error?


Because we are talking about the population distribution, not a sample statistic.
作者: pogo    时间: 2011-7-11 18:38

I'm not sure if my method is right, I just remember estimating it from college stats class.

We know that in a normal distribution:

68% is +/- one standard deviation
95% is +/- two standard deviations
99% is +/- three standard deviations

so at 99% there is a range of six standard deviations

480,000-230,000 = 250,000

250,000/6 = 41,666
作者: trogulj    时间: 2011-7-11 18:38

Interesting way of looking at the problem using Chebyshev's inequality. Here is the answer explanation as per CFAI.


"Given that the sales are normally distributed, the mean is centered in the interval.
Mean = (230+480)/2 = 355. 99% of observations under a normal distribution will be +/- 3 std devs. Thus (355-230)/3 = 41,667. It is also the case that (480-355)/3 = 41,667."




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