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标题: Reading 11: Hypothesis Testing - LOS a, (Part 3) ~ Q6-10 [打印本页]

作者: mayanfang1    时间: 2009-1-13 15:52     标题: [2009] Session 3 - Reading 11: Hypothesis Testing - LOS a, (Part 3) ~ Q6-10

Q6. If the null hypothesis is H0: ρ ≤ 0, what is the appropriate alternative hypothesis?

A)     Ha: ρ ≠ 0.

B)     Ha: ρ > 0.

C)     Ha: ρ < 0.

Q7. In order to test if the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the sample value of the computed test statistic, tn-1 = 1.2. If you choose a 5% significance level you should:

A)   fail to reject the null hypothesis and conclude that the population mean is not greater than 100.

B)   reject the null hypothesis and conclude that the population mean is greater than 100.

C)   fail to reject the null hypothesis and conclude that the population mean is greater than 100.

Q8. In order to test whether the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the sample value of the computed test statistic, tn-1 = 3.4. The null and alternative hypotheses are:

A)H0: µ ≤ 100; Ha: µ > 100.

B)H0: µ = 100; Ha: µ ≠ 100.

C)H0: X ≤ 100; Ha: X > 100.

Q9. In a two-tailed test of a hypothesis concerning whether a population mean is zero, Jack Olson computes a t-statistic of 2.7 based on a sample of 20 observations where the distribution is normal. If a 5% significance level is chosen, Olson should:

A)   reject the null hypothesis and conclude that the population mean is not significantly different from zero.

B)   fail to reject the null hypothesis that the population mean is not significantly different from zero.

C)   reject the null hypothesis and conclude that the population mean is significantly different from zero.

Q10. What kind of test is being used for the following hypothesis and what would a z-statistic of 1.68 tell us about a hypothesis with the appropriate test and a level of significance of 5%, respectively?

H0: B ≤ 0

HA: B > 0

A)   One-tailed test; fail to reject the null.

B)   Two-tailed test; fail to reject the null.

C)   One-tailed test; reject the null.


作者: mayanfang1    时间: 2009-1-13 15:53

答案和详解如下:

Q6. If the null hypothesis is H0: ρ ≤ 0, what is the appropriate alternative hypothesis?

A)     Ha: ρ ≠ 0.

B)     Ha: ρ > 0.

C)     Ha: ρ < 0.

Correct answer is B)

The alternative hypothesis must include the possible outcomes the null does not.

Q7. In order to test if the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the sample value of the computed test statistic, tn-1 = 1.2. If you choose a 5% significance level you should:

A)   fail to reject the null hypothesis and conclude that the population mean is not greater than 100.

B)   reject the null hypothesis and conclude that the population mean is greater than 100.

C)   fail to reject the null hypothesis and conclude that the population mean is greater than 100.

Correct answer is A)

At a 5% significance level, the critical t-statistic using the Student’s t distribution table for a one-tailed test and 29 degrees of freedom (sample size of 30 less 1) is 1.699 (with a large sample size the critical z-statistic of 1.645 may be used). Because the critical t-statistic is greater than the calculated t-statistic, meaning that the calculated t-statistic is not in the rejection range, we fail to reject the null hypothesis and we conclude that the population mean is not significantly greater than 100.

Q8. In order to test whether the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the sample value of the computed test statistic, tn-1 = 3.4. The null and alternative hypotheses are:

A)H0: µ ≤ 100; Ha: µ > 100.

B)H0: µ = 100; Ha: µ ≠ 100.

C)H0: X ≤ 100; Ha: X > 100.

Correct answer is A)

The null hypothesis is that the theoretical mean is not significantly different from zero. The alternative hypothesis is that the theoretical mean is greater than zero.

Q9. In a two-tailed test of a hypothesis concerning whether a population mean is zero, Jack Olson computes a t-statistic of 2.7 based on a sample of 20 observations where the distribution is normal. If a 5% significance level is chosen, Olson should:

A)   reject the null hypothesis and conclude that the population mean is not significantly different from zero.

B)   fail to reject the null hypothesis that the population mean is not significantly different from zero.

C)   reject the null hypothesis and conclude that the population mean is significantly different from zero.

Correct answer is C)

At a 5% significance level, the critical t-statistic using the Student’s t-distribution table for a two-tailed test and 19 degrees of freedom (sample size of 20 less 1) is ± 2.093 (with a large sample size the critical z-statistic of 1.960 may be used). Because the critical t-statistic of 2.093 is to the left of the calculated t-statistic of 2.7, meaning that the calculated t-statistic is in the rejection range, we reject the null hypothesis and we conclude that the population mean is significantly different from zero.

Q10. What kind of test is being used for the following hypothesis and what would a z-statistic of 1.68 tell us about a hypothesis with the appropriate test and a level of significance of 5%, respectively?

H0: B ≤ 0

HA: B > 0

A)   One-tailed test; fail to reject the null.

B)   Two-tailed test; fail to reject the null.

C)   One-tailed test; reject the null.

Correct answer is C)

The way the alternative hypothesis is written you are only looking at the right side of the distribution. You are only interested in showing that B is greater than 0. You don't care if it is less than zero. For a one-tailed test at the 5% level of significance, the critical z value is 1.645. Since the test statistic of 1.68 is greater than the critical value we would reject the null hypothesis.


作者: jacky_z    时间: 2009-2-17 13:09

Thanks
作者: zeraeh    时间: 2009-2-17 21:41

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 B A A C C 对吗?

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Q5. In order to test whether the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the sample value of the computed test statistic, tn-1 = 3.4. If you choose a 5% significance level you should:

A)   fail to reject the null hypothesis and conclude that the population mean is less than or equal to 100.

B)   fail to reject the null hypothesis and conclude that the population mean is greater than 100.

C)   reject the null hypothesis and conclude that the population mean is greater that 100.

Correct answer is C)

At a 5% significance level, the critical t-statistic using the Student’s t distribution table for a one-tailed test and 29 degrees of freedom (sample size of 30 less 1) is 1.699 (with a large sample size the critical z-statistic of 1.645 may be used). Because the calculated t-statistic of 3.4 is greater than the critical t-statistic of 1.699, meaning that the calculated t-statistic is in the rejection range, we reject the null hypothesis and we conclude that the population mean is greater than 100.

Q6. In a two-tailed hypothesis test, Jack Olson observes a t-statistic of -1.38 based on a sample of 20 observations where the population mean is zero. If you choose a 5% significance level, you should:

A)   fail to reject the null hypothesis that the population mean is not significantly different from zero.

B)   reject the null hypothesis and conclude that the population mean is significantly different from zero.

C)   reject the null hypothesis and conclude that the population mean is not significantly different from zero.

Correct answer is A)

At a 5% significance level, the critical t-statistic using the Student’s t distribution table for a two-tailed test and 19 degrees of freedom (sample size of 20 less 1) is ± 2.093 (with a large sample size the critical z-statistic of 1.960 may be used). Because the critical t-statistic of -2.093 is to the left of the calculated t-statistic of -1.38, meaning that the calculated t-statistic is not in the rejection range, we fail to reject the null hypothesis that the population mean is not significantly different from zero.

Q7. The table below is for five samples drawn from five separate populations. The far left columns give information on the population distribution, population variance, and sample size. The right-hand columns give three choices for the appropriate tests: z = z-statistic, and t = t-statistic. “None” means that a test statistic is not available.

Sampling From

Test Statistic Choices

Distribution

Variance

n

One

Two

Three

 

Non-normal

0.75

100

z

z

z

 

Normal

5.60

75

z

z

z

 

Non-normal

n/a

15

t

t

none

 

Normal

n/a

18

t

t

t

 

Non-normal

14.3

15

z

t

none

 

Which set of test statistic choices (One, Two, or Three) matches the correct test statistic to the sample for all five samples?

A)   Three.

B)   One.

C)   Two.

Correct answer is A)

For the exam: COMMIT THE FOLLOWING TABLE TO MEMORY!

When you are sampling from a:

and the sample size is small, use a:

and the sample size is large, use a:

Normal distribution with a known variance

z-statistic

z-statistic

Normal distribution with an unknown variance

t-statistic

t-statistic

Nonnormal distribution with a known variance

not available

z-statistic

Nonnormal distribution with an unknown variance

not available

t-statistic

Q8. A survey is taken to determine whether the average starting salaries of CFA charterholders is equal to or greater than $62,500 per year. What is the test statistic given a sample of 125 newly acquired CFA charterholders with a mean starting salary of $65,000 and a standard deviation of $2,600?

A)   -10.75.

B)   0.96.

C)   10.75.

Correct answer is C)

With a large sample size (125) and an unknown population variance, either the t-statistic or the z-statistic could be used. Using the z-statistic, it is calculated by subtracting the hypothesized parameter from the parameter that has been estimated and dividing the difference by the standard error of the sample statistic. The test statistic = (sample mean – hypothesized mean) / (sample standard deviation / (sample size1/2)) = (X ? μ) / (s / n1/2) = (65,000 – 62,500) / (2,600 / 1251/2) = (2,500) / (2,600 / 11.18) = 10.75.



作者: ch_914    时间: 2009-7-20 19:30

THANKS
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作者: windmind21    时间: 2010-12-26 07:19

 Actually I have to say that I hate hypothesis test I never really got them sorted out

作者: 祈愿修神    时间: 2011-4-6 14:59

1
作者: kepei7763    时间: 2011-5-28 20:44

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作者: FOREVER396    时间: 2011-6-19 11:26

haveA LOOK
作者: shannyzheng    时间: 2011-8-11 15:42

what is the answer?
作者: shing1314    时间: 2011-8-19 16:44

thanks for sharing




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