1. [(E(r)-2%)/standard deviation]=z=1.3, z~N(0,1), so the answer is the one on the z-table for z=-1.3, which is 0.9068
2. the meaning of this question is P[(x-Ex)>2*(standard deviation)]= [(x-Ex)/(standard deviation)>2], for the same reasoning as no.1 question, the answer is the figure related to z=-2 from the z-table. |