The correct answer is A
T=145/365 = 0.39726
d1 = [ln(27/30) + [.04 + .32/2](.39726)] / (.3√.39726)
= (-.10536052 + .0337671) / .18908569
= -.07159342 / .18908569
= -0.37863 d1 = -0.37863 ≈ -0.38 N(d1) = 1 -0.6480 = 0.3520
d2 = -0.37863 - .3√.39726
= -0.37863 - .18908569
= -.56771569
= -.56772 d2 = -0.56772 ≈ -0.57 N(d2) = 1 - 0.7157 = 0.2843
PT = 30e-.04(.39726) (1-.2843) – 27(1-.352)
= (29.527056 × .7157) – 17.496
= 21.1325 – 17.496 p = $3.64 |