An analyst is testing to see if the mean of a population is less than 133. A random sample of 50 observations had a mean of 130. Assume a standard deviation of 5. The test is to be made at the 1% level of significance.
z |
0.00 |
0.01 |
0.02 |
0.03 |
0.04 |
0.05 |
0.06 |
0.0 |
0.0000 |
0.0040 |
0.0080 |
0.0120 |
0.0160 |
0.0199 |
0.0239 |
0.1 |
0.0398 |
0.0438 |
0.0478 |
0.0517 |
0.0557 |
0.0596 |
0.0636 |
0.2 |
0.0793 |
0.0832 |
0.0871 |
0.0910 |
0.0948 |
0.0987 |
0.1026 |
0.3 |
0.1179 |
0.1217 |
0.1255 |
0.1293 |
0.1331 |
0.1368 |
0.1406 |
| |
| |
| |
| |
| |
| |
| |
| |
1.7 |
0.4554 |
0.4564 |
0.4573 |
0.4582 |
0.4591 |
0.4599 |
0.4608 |
1.8 |
0.4641 |
0.4649 |
0.4656 |
0.4664 |
0.4671 |
0.4678 |
0.4686 |
1.9 |
0.4713 |
0.4719 |
0.4726 |
0.4732 |
0.4738 |
0.4744 |
0.4750 |
2.0 |
0.4772 |
0.4778 |
0.4783 |
0.4788 |
0.4793 |
0.4798 |
0.4803 |
2.1 |
0.4821 |
0.4826 |
0.4830 |
0.4834 |
0.4838 |
0.4842 |
0.4846 |
2.2 |
0.4861 |
0.4864 |
0.4868 |
0.4871 |
0.4875 |
0.4878 |
0.4881 |
2.3 |
0.4893 |
0.4896 |
0.4898 |
0.4901 |
0.4904 |
0.4906 |
0.4909 |
2.4 |
0.4918 |
0.4920 |
0.4922 |
0.4925 |
0.4927 |
0.4929 |
0.4931 |
The null hypothesis is:
The null hypothesis is the hypothesis that the researcher wants to reject. Here the hypothesis that is being looked for is that the mean of a population is less than 133. The null hypothesis is that the mean is greater than or equal to 133. The question is whether the null hypothesis will be rejected in favor of the alternative hypothesis that the mean is less than 133.
The calculated test statistic is:
A test statistic is calculated by subtracting the hypothesized parameter from the parameter that has been estimated and dividing the difference by the standard error of the sample statistic. Here, the test statistic = (sample mean – hypothesized mean) / ((sample standard deviation / (sample size)1/2)) = (130 – 133) / (5 / 501/2) = (-3) / (5 / 7.0711) = -4.24.
The critical value is:
This is a one-tailed test with a significance level of 0.01. The critical value for a one-tailed test at a 1% level of significance is -2.33.
You should:
A) |
reject the null hypothesis. | |
B) |
reject the alternative hypothesis. | |
C) |
accept the null hypothesis. | |
The calculated test statistic of -4.24 falls to the left of the z-statistic of -2.33, and is in the rejection region. Thus, the null hypothesis is rejected and the conclusion is that the population mean is less than 133. |