3975

答案和详解如下：

26 Correct answer is A

“Statistical Concepts and Market Returns,” Richard A. Defusco, Dennis W. McLeavey, Jerald E. Pinto, and David E. Runkel
2008 Modular Level I, Vol. 1, pp. 291-297
Study Session 2-7-h
define, calculate, and interpret the coefficient of variation and the Sharpe ratio

27 Correct answer is D

“Probability Concepts,” Richard A. Defusco, Dennis W. McLeavey, Jerald E. Pinto, and David E. Runkel
2008 Modular Level I, Vol. 1, pp. 319-320
Study Session 2-8-b
explain the two defining properties of probability, and distinguish among empirical, subjective, and a priori probabilities
An empirical probability cannot be calculated for an event not in the historical record. In this case, the analyst can make a personal assessment of the probability of the event without reference to any particular data. This is a subjective probability.

28 Correct answer is D

“Probability Concepts,” Richard A. Defusco, Dennis W. McLeavey, Jerald E. Pinto, and David E. Runkel
2008 Modular Level I, Vol. 1, pp. 342-347
Study Session 2-8-j
calculate and interpret covariance and correlation
The correlation between two random variables is equal to the covariance between the variables divided by the product of the variables’ standard deviations.

29 Correct answer is A

“Common Probability Distributions,” Richard A. Defusco, Dennis W. McLeavey, Jerald E. Pinto, and David E. Runkel
2008 Modular Level I, Vol. 1, pp. 373-374
Study Session 2-9-d
define a discrete uniform random variable and a binomial random variable, calculate and interpret probabilities given the discrete uniform and the binomial distribution functions, and construct a binomial tree to describe stock price movement
The discrete uniform distribution is known as the simplest of all probability distributions. It is made up of a finite number of specified outcomes and each outcome is equally likely.

30 Correct answer is C

“Common Probability Distributions,” Richard A. Defusco, Dennis W. McLeavey, Jerald E. Pinto, and David E. Runkel
2008 Modular Level I, Vol. 1, pp. 392-393
Study Session 2-9-g
construct and interpret a confidence interval for a normally distributed random variable, and determine the probability that a normally distributed random variable lies inside a given confidence interval
The 99% confidence interval for a normally distributed random variable is equal to the sample mean ± 2.58 x sample standard deviation. In this case, the 99% confidence interval = 42 ± (2.58 x 90.5) = 42 ± (2.58 x 3) = 42 ± 7.74 ≈ 34.3 to 49.7.