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What does it mean to say that an observation is at the sixty-fifth percentile?
A)
65% of all the observations are below that observation.
B)
65% of all the observations are above that observation.
C)
The observation falls within the 65th of 100 intervals.



If the observation falls at the sixty-fifth percentile, 65% of all the observations fall below that observation.

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What are the median and the third quintile of the following data points, respectively?
9.2%, 10.1%, 11.5%, 11.9%, 12.2%, 12.8%, 13.1%, 13.6%, 13.9%, 14.2%, 14.8%, 14.9%, 15.4%
A)
13.1%; 13.6%.
B)
13.1%; 13.7%.
C)
12.8%; 13.6%.



The median is the midpoint of the data points. In this case there are 13 data points and the midpoint is the 7th term.
The formula for determining quantiles is: Ly = (n + 1)(y) / (100). Here, we are looking for the third quintile (60% of the observations lie below) and the formula is: (14)(60) / (100) = 8.4. The third quintile falls between 13.6% and 13.9%, the 8th and 9th numbers from the left. Since L is not a whole number, we interpolate as: 0.136 + (0.40)(0.139 − 0.136) = 0.1372, or 13.7%.

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Which of the following statements about the median is least accurate? It is:
A)
equal to the 50th percentile.
B)
more affected by extreme values than the mean.
C)
equal to the mode in a normal distribution.



Median is less influenced by outliers since the median is computed as the “middle” observation. On the other hand, all of the data including outliers are used in computing the mean. Both remaining statements are true regarding the median.

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Which of the following statements about the arithmetic mean is least accurate?
A)
The arithmetic mean of a frequency distribution is equal to the sum of the class frequency times the midpoint of the frequency class all divided by the number of observations.
B)
If the distribution is skewed to the left then the mean will be greater than the median.
C)
The arithmetic mean is the only measure of central tendency where the sum of the deviations of each observation from the mean is always zero.



If the distribution is skewed to the left, then the mean will be less than the median.

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A portfolio is equally invested in Stock A, with an expected return of 6%, and Stock B, with an expected return of 10%, and a risk-free asset with a return of 5%. The expected return on the portfolio is:
A)
7.0%.
B)
8.0%.
C)
7.4%.



(0.333)(0.06) + (0.333)(0.10) + 0.333(0.05) = 0.07

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An investor has the following assets:
  • $5,000 in bonds with an expected return of 8%.
  • $10,000 in equities with an expected return of 12%.
  • $5,000 in real estate with an expected return of 10%.

What is the portfolio's expected return?
A)
10.00%.
B)
11.00%.
C)
10.50%.



Expected return is the weighted average of the individual expected values. The expected return is: [(5,000) × (10.00) + (5,000) × (8.00) + (10,000) × (12.00)] / 20,000 = 10.50%.

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Which of the following statements about a normal distribution is least accurate?
A)
Approximately 68% of the observations lie within +/- 1 standard deviation of the mean.
B)
A normal distribution has excess kurtosis of three.
C)
The mean and variance completely define a normal distribution.



Even though normal curves have different sizes, they all have identical shape characteristics. The kurtosis for all normal distributions is three; an excess kurtosis of three would indicate a leptokurtic distribution. Both remaining choices are true.

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An investor has a portfolio with 10% cash, 30% bonds, and 60% stock. If last year’s return on cash was 2.0%, the return on bonds was 9.5%, and the return on stock was 25%, what was the return on the investor’s portfolio?
A)
36.50%.
B)
18.05%.
C)
22.30%.



Find the weighted mean of the returns. (0.10 × 0.02) + (0.30 × 0.095) + (0.60 × 0.25) = 18.05%

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An investor has a $15,000 portfolio consisting of $10,000 in stock A with an expected return of 20% and $5,000 in stock B with an expected return of 10%. What is the investor’s expected return on the portfolio?
A)
12.2%.
B)
7.9%.
C)
16.7%.



Find the weighted mean where the weights equal the proportion of $15,000. [(10,000 / 15,000) × 0.20] + [(5,000 / 15,000 × 0.10] = 16.7%.

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Find the mean, median, and mode, respectively, of the following data:

3, 3, 5, 8, 9, 13, 17
A)
8; 8.28; 3.
B)
8.28; 8; 3.
C)
3; 8.28; 8.



Mean = (3 + 3 + 5 + 8 + 9 + 13 + 17) / 7 = 8.28; Median = middle of distribution = 8 (middle number); Mode = most frequent = 3.

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