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- 2011-7-11
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- 2016-4-19
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12#
发表于 2011-7-13 13:58
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Since you'll probably end with a lot of time remaining, I would count up all the A, B, and C. I know each answer is independent, so having all A as answer is just as likely as all B, etc.
But I'd like to think that having 40 A, 40 B, and 40 C is more likely. I also like to think that clusters are more likely to be broken up by opposites. If A and B have been switching off in the last 3-4 answers, then I choose C.
It becomes a game of roulette and can be mildly more entertaining than sitting around. Again, I know every answer choice is independent, but I've never taken a test where a single number came up more than 7 times in a row. |
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