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 UID223415 帖子346 主题18 注册时间2011-7-11 最后登录2014-7-31 
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2#
 
 发表于 2011-7-13 14:33 
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| Way to confuse. Throw in a quant question, and stare at the blank faces of candidates. 
 By the way i'd think the answer to your question is NO.
 
 SEE = std deviation of error terms.
 SEE = sqrt(variance of error)
 SEE = sqrt(SSE/n-k-1)
 
 where as MSE = SSE/ n-k-1 <-- there is no square root here.
 SSE = squared sum of all errors, or residual sum of errors.
 
 SSE/n-k-1 is not equal to SEE.
 
 By the way what is RMSE? seeing it for the first time.
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