标题: Reading 9: Common Probability Distributions - LOS h, (Part [打印本页]
作者: mayanfang1 时间: 2009-1-9 10:31 标题: [2009] Session 3- Reading 9: Common Probability Distributions - LOS h, (Part
Q1. The average annual rainfall amount in Yucutat, Alaska, is normally distributed with a mean of 150 inches and a standard deviation of 20 inches. The 90% confidence interval for the annual rainfall in Yucutat is closest to:
A) 117 to 183 inches.
B) 110 to 190 inches.
C) 137 to 163 inches.
Q2. The standard normal distribution is most completely described as a:
A) distribution that exhibits zero skewness and no excess kurtosis.
B) symmetrical distribution with a mean equal to its median.
C) normal distribution with a mean of zero and a standard deviation of one.
Q3. Monthly sales of hot water heaters are approximately normally distributed with a mean of 21 and a standard deviation of 5. What is the probabilility of selling 12 hot water heaters or less next month?
A) 3.59%.
B) 1.80%.
C) 96.41%.
作者: mayanfang1 时间: 2009-1-9 10:33
答案和详解如下:
Q1. The average annual rainfall amount in Yucutat, Alaska, is normally distributed with a mean of 150 inches and a standard deviation of 20 inches. The 90% confidence interval for the annual rainfall in Yucutat is closest to:
A) 117 to 183 inches.
B) 110 to 190 inches.
C) 137 to 163 inches.
Correct answer is A)
The 90% confidence interval is µ ± 1.65 standard deviations. 150 − 1.65(20) = 117 and 150 + 1.65(20) = 183.
Q2. The standard normal distribution is most completely described as a:
A) distribution that exhibits zero skewness and no excess kurtosis.
B) symmetrical distribution with a mean equal to its median.
C) normal distribution with a mean of zero and a standard deviation of one.
Correct answer is C)
The standard normal distribution is defined as a normal distribution that has a mean of zero and a standard deviation of one. The other choices apply to any normal distribution.
Q3. Monthly sales of hot water heaters are approximately normally distributed with a mean of 21 and a standard deviation of 5. What is the probabilility of selling 12 hot water heaters or less next month?
A) 3.59%.
B) 1.80%.
C) 96.41%.
Correct answer is A)
Z = (12 – 21) / 5 = -1.8
From the cumulative z-table, the probability of being more than 1.8 standard deviations below the mean, probability x < -1.8, is 3.59%.
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