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标题: Reading 11: Hypothesis Testing - LOS e, (Part 3) ~ Q2-4 [打印本页]

作者: mayanfang1    时间: 2009-1-13 16:13     标题: [2009] Session 3 - Reading 11: Hypothesis Testing - LOS e, (Part 3) ~ Q2-4

Q2. Joe Sutton is evaluating the effects of the 1987 market decline on the volume of trading. Specifically, he wants to test whether the decline affected trading volume. He selected a sample of 500 companies and collected data on the total annual volume for one year prior to the decline and for one year following the decline. What is the set of hypotheses that Sutton is testing?

A)   H0: µd = µd0 versus Ha: µd ≠ µd0.

B)   H0: µd ≠ µd0 versus Ha: µd = µd0.

C)   H0: µd = µd0 versus Ha: µd > µd0.

Q3. An analyst wants to determine whether the monthly returns on two stocks over the last year were the same or not. What test should she use if she is willing to assume that the returns are normally distributed?

A)   A difference in means test only if the variances of monthly returns are equal for the two stocks.

B)   A paired comparisons test because the samples are not independent.

C)   A difference in means test with pooled variances from the two samples.

Q4. An analyst for the entertainment industry theorizes that betas for most firms in the industry are higher after September 11, 2001. She sampled 31 firms comparing their betas for the one-year period before and after this date. Based on this sample, she found that the mean differences in betas were 0.19, with a sample standard deviation of 0.11. Her null hypothesis is that the betas are the same before and after September 11. Based on the results of her sample, can we reject the null hypothesis at a 5% significance level and why? Null is:

A)   not rejected. The critical value exceeds the t-value by 7.58.

B)   rejected. The t-value exceeds the critical value by 5.67.

C)   rejected. The t-value exceeds the critical value by 7.58.


作者: mayanfang1    时间: 2009-1-13 16:13

答案和详解如下:

Q2. Joe Sutton is evaluating the effects of the 1987 market decline on the volume of trading. Specifically, he wants to test whether the decline affected trading volume. He selected a sample of 500 companies and collected data on the total annual volume for one year prior to the decline and for one year following the decline. What is the set of hypotheses that Sutton is testing?

A)   H0: µd = µd0 versus Ha: µd ≠ µd0.

B)   H0: µd ≠ µd0 versus Ha: µd = µd0.

C)   H0: µd = µd0 versus Ha: µd > µd0.

Correct answer is A)

This is a paired comparison because the sample cases are not independent (i.e., there is a before and an after for each stock). Note that the test is two-tailed, t-test.

Q3. An analyst wants to determine whether the monthly returns on two stocks over the last year were the same or not. What test should she use if she is willing to assume that the returns are normally distributed?

A)   A difference in means test only if the variances of monthly returns are equal for the two stocks.

B)   A paired comparisons test because the samples are not independent.

C)   A difference in means test with pooled variances from the two samples.

Correct answer is B)

A paired comparisons test must be used. The difference in means test requires that the samples be independent. Portfolio theory teaches us that returns on two stocks over the same time period are unlikely to be independent since both have some systematic risk.

Q4. An analyst for the entertainment industry theorizes that betas for most firms in the industry are higher after September 11, 2001. She sampled 31 firms comparing their betas for the one-year period before and after this date. Based on this sample, she found that the mean differences in betas were 0.19, with a sample standard deviation of 0.11. Her null hypothesis is that the betas are the same before and after September 11. Based on the results of her sample, can we reject the null hypothesis at a 5% significance level and why? Null is:

A)   not rejected. The critical value exceeds the t-value by 7.58.

B)   rejected. The t-value exceeds the critical value by 5.67.

C)   rejected. The t-value exceeds the critical value by 7.58.

Correct answer is C)         

The t-statistic for paired differences:

t = (dud 0) / sd and sd = sd / √n

t = 9.62 from a table with 30 df, the critical value = 2.042


作者: zeraeh    时间: 2009-2-17 21:54

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Q6. If the null hypothesis is H0: ρ ≤ 0, what is the appropriate alternative hypothesis?

A)     Ha: ρ ≠ 0.

B)     Ha: ρ > 0.

C)     Ha: ρ < 0.

Correct answer is B)

The alternative hypothesis must include the possible outcomes the null does not.

Q7. In order to test if the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the sample value of the computed test statistic, tn-1 = 1.2. If you choose a 5% significance level you should:

A)   fail to reject the null hypothesis and conclude that the population mean is not greater than 100.

B)   reject the null hypothesis and conclude that the population mean is greater than 100.

C)   fail to reject the null hypothesis and conclude that the population mean is greater than 100.

Correct answer is A)

At a 5% significance level, the critical t-statistic using the Student’s t distribution table for a one-tailed test and 29 degrees of freedom (sample size of 30 less 1) is 1.699 (with a large sample size the critical z-statistic of 1.645 may be used). Because the critical t-statistic is greater than the calculated t-statistic, meaning that the calculated t-statistic is not in the rejection range, we fail to reject the null hypothesis and we conclude that the population mean is not significantly greater than 100.

Q8. In order to test whether the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the sample value of the computed test statistic, tn-1 = 3.4. The null and alternative hypotheses are:

A)H0: μ ≤ 100; Ha: μ > 100.

B)H0: μ = 100; Ha: μ ≠ 100.

C)H0: X ≤ 100; Ha: X > 100.

Correct answer is A)

The null hypothesis is that the theoretical mean is not significantly different from zero. The alternative hypothesis is that the theoretical mean is greater than zero.

Q9. In a two-tailed test of a hypothesis concerning whether a population mean is zero, Jack Olson computes a t-statistic of 2.7 based on a sample of 20 observations where the distribution is normal. If a 5% significance level is chosen, Olson should:

A)   reject the null hypothesis and conclude that the population mean is not significantly different from zero.

B)   fail to reject the null hypothesis that the population mean is not significantly different from zero.

C)   reject the null hypothesis and conclude that the population mean is significantly different from zero.

Correct answer is C)

At a 5% significance level, the critical t-statistic using the Student’s t-distribution table for a two-tailed test and 19 degrees of freedom (sample size of 20 less 1) is ± 2.093 (with a large sample size the critical z-statistic of 1.960 may be used). Because the critical t-statistic of 2.093 is to the left of the calculated t-statistic of 2.7, meaning that the calculated t-statistic is in the rejection range, we reject the null hypothesis and we conclude that the population mean is significantly different from zero.

Q10. What kind of test is being used for the following hypothesis and what would a z-statistic of 1.68 tell us about a hypothesis with the appropriate test and a level of significance of 5%, respectively?

H0: B ≤ 0

HA: B > 0

A)   One-tailed test; fail to reject the null.

B)   Two-tailed test; fail to reject the null.

C)   One-tailed test; reject the null.

Correct answer is C)

The way the alternative hypothesis is written you are only looking at the right side of the distribution. You are only interested in showing that B is greater than 0. You don't care if it is less than zero. For a one-tailed test at the 5% level of significance, the critical z value is 1.645. Since the test statistic of 1.68 is greater than the critical value we would reject the null hypothesis.


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作者: 璀璨    时间: 2010-8-18 11:48     标题: 爱情与幸福

爱情与幸福
爱情是甜蜜的,也是苦涩的。也许很多文学作品会把爱情描写得太过于完美,过于浪漫,过于神圣,但现实中的爱情,往往充满着痛苦,充满着无奈!
被爱
  当一个人爱你爱得发疯,而你对其没有半点感觉的时候,也许你会感受到一丝被爱的虚荣,但更多的,是一种烦恼,一种愧疚。  爱你的人,总是会出现在你出现的地方,或许他(她)会称其为“缘份”,但天晓得所谓的“缘份”是不是其故意安排。爱你的人,有时就像打探明星隐私的“狗仔队”,让你避无可避,烦恼透顶。而且,他(她)总是会公然地,或者默默地帮你的忙,为你打点周围的琐事。爱你的人称其为“爱的付出”,然而,这实质上是一种投资,一种感情的投资。有付出,也必然渴望得到爱的回报。就是因为明白这一点,对于被爱的人来说,得到对方的帮助越多,心里的愧疚感就越重,好比借了别人一大笔钱而无力偿还一样。[url=http:zhengxing.51.am/2010/0612/194815.html]郑州整形美容医院[/url]  拒绝对方,是对别人的一种伤害;接受对方,是对自己的残忍!无论你作任何一种选择,总得面对伤痛。
单恋
  落花有意,可惜流水无情!单恋[url=http:zhengxing.51.am/2010/0612/194836.html]隆胸手术视频[/url],即所谓的“单相思”,更是折磨人,伤害人。  对于你所爱的人,因为她不爱你,所以你只能远远地欣赏她的倩影。心中即便有万千爱的宣言,也只能埋藏在内心深处,苦苦地压抑。越是痴痴地爱,越是深深地痛!
  记得《明知道相思苦》的一句歌词:认识你之前,是无靠无依,认识你后无药可医!其实,还有一种药可以治好“相思病”?对方的爱!心病还得心药医,解铃还须系铃人也。
  只可惜,既然是“单恋”,那就是说,此病的解药是永远也得不到的,也算是“无药可医”吧!只能让时间流逝,将伤痛慢慢地带走……
相思
  花自飘零,水自流。一种相思,两处闲愁,此情无计可消除,才下眉头,却上心头!
  这时所说的“相思”,是两情相悦的思念,在惆怅中往往带着一丝甜蜜和幸福。因为这是对恋人的思念,你的恋人也可能在遥远的另一个地方与你共鸣。
  但是,这种相思之苦比单恋来得更加深沉,更加难熬,更加无法自拔。[url=http:zhengxing.51.am/2010/0413/shjyzxwk.html]上海九院整形外科[/url]一日不见,如隔三秋!即使心里竭力不去想她,梦里还是会梦到她,醒来之后,发现一切依旧,只会更相思。
  相思之人,往往茶饭不思,夜不能寐,一段时间一来,脸色愈加憔悴,人也逐渐消瘦。于是有词云:衣带渐宽终不悔,为伊消得人憔悴!
猜疑
  恋人之间,也许彼此太在乎对方,常常会害怕对方的移情别恋,恨不能用一个永远也打不开的保险柜把对方的爱锁起来,免得让它与外边的空气接触而发生变质。
  因此,情人不仅是情人,还是“神探福尔摩斯”:对方一有任何出轨的迹象,一定会暗暗留心,或者当面质问。怪不得现在的爱情类书籍中,都有这样一条“忠告”:在女朋友或者妻子面前,[url=http:zhengxing.51.am/2010/0630/197214.html]瘦脸针多少钱[/url]切不可称赞其他的女人;在男朋友或者是丈夫面前,切不可赞扬其他的男人!
  所以即使两个人在一起,还是不能畅情惬意,得留出一份心思来观察对方的动静,还得担心对方会不会禁受不住外界的诱惑而变心,尤其是对方因为工作原因而跟其他异性交触较多时,更是充满了危机感。
  要想享受爱情的幸福,就必须回避这些爱情的痛苦。因此[url=http:zhengxing.51.am/2010/0612/hzzxyydjyxmynx.html]杭州整形医院[/url],真正幸福的爱情应该是:两情相悦,两人厮守,彼此信任!








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