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I'm not sure if my method is right, I just remember estimating it from college stats class.

We know that in a normal distribution:

68% is +/- one standard deviation
95% is +/- two standard deviations
99% is +/- three standard deviations

so at 99% there is a range of six standard deviations

480,000-230,000 = 250,000

250,000/6 = 41,666

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