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- 2014-8-4
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Let X be the random variable which describes the annual return. Given, XBar = +10% and sigma = +6%
The question is to find the probability, P (returns falling below 2%) = P (returns
The z-score is calculated as z-score = ( X - XBar ) / sigma = ( -2 - 10 ) / 6 = -2
Assuming normal distribution, the probability P(returns
Is (A) the right answer? |
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发表于 2013-4-28 06:59
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